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Home/ Questions/Q 6837233
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T23:27:11+00:00 2026-05-26T23:27:11+00:00

Hi I have a query like so SELECT videos.*, categories.cat_name , ( SELECT COUNT(

  • 0

Hi I have a query like so

SELECT 
    videos.*, 
    categories.cat_name , 
    ( SELECT COUNT( * ) AS count FROM user_favorites WHERE user_id = 'tw415656866' AND video_id = videos.video_id )is_favorite 
FROM `videos` 
INNER JOIN categories 
    ON categories.cat_id = videos.cat_id 
WHERE 
    date <= '2011-11-21 09:12:18' 
GROUP BY videos.video_id 
ORDER BY (votesdown / votesup) ASC 
LIMIT 0, 5 

This code works fine and returns a table like below

video_id     – video id
cat_name   – category name
cat_id         – category id
title             – video title
yt_id           – youtubes video id
votesup      – votes up
votesdown  – votes down
date            – date added
tweeted       – 0 / 1 ( 1=tweeted)
is_favorite   – 0 / 1 ( 1=favorited)

What i’m trying to do is add this to the WHERE clause

AND is_favorite = 1

As you can see ‘is_favorite’ is added to the dataset as a column but I cannot query it because MySQL says the column ‘is_favorite’ doesn’t exist.

The exact error is…
” Unknown column ‘is_favorite’ in ‘where clause’ “

Any ideas?

Thanks alot

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T23:27:11+00:00Added an answer on May 26, 2026 at 11:27 pm

    is_favorite is indeed not a column but an alias for your subquery. Try using

    HAVING is_favorite = 1
    

    instead. See for example http://www.w3schools.com/sql/sql_having.asp for an explanation of the difference between WHERE and HAVING

    So your query should look like this:

    SELECT 
        videos.*, 
        categories.cat_name , 
        ( SELECT COUNT( * ) AS count FROM user_favorites WHERE user_id = 'tw415656866' AND video_id = videos.video_id ) AS is_favorite 
    FROM `videos` 
    INNER JOIN categories ON categories.cat_id = videos.cat_id 
    WHERE date <= '2011-11-21 09:12:18' 
    GROUP BY videos.video_id 
    HAVING is_favorite = 1
    ORDER BY (votesdown / votesup) ASC 
    LIMIT 0, 5 
    
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