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Home/ Questions/Q 3783950
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T11:18:10+00:00 2026-05-19T11:18:10+00:00

hi i have a sitemap xml document that looks something like this <pagenode title=home

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hi
i have a sitemap xml document that looks something like this

<pagenode title="home" url="~/" fornavbar="true">
 <pagenode title="admin" url="~/admin" fornavbar="false">
  <pagenode title="users" url="~/admin/users" fornavbar="false"/>
  <pagenode title="events" url="~/admin/events" fornavbar="true"/>
 </pagenode>
 <pagenode title="catalog" url="~/catalog" fornavbar="true"/>
 <pagenode title="contact us" url="~/contactus" fornavbar="false"/>
</pagenode>

now i want to retrieve an xml document for the navbar, which includes all the pagenodes that have fornavbar=true. how can this be done?

the closest i was able to get so far was this:

<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:template match="pagenode[@fornavbar='true']">
  <xsl:copy-of select="."/>
 </xsl:template>
</xsl:stylesheet>

the problem with this is that includes all the children of anything matched as navbar

i only want to copy all the attributes, not all the children

but if i try

<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:template match="pagenode[@fornavbar='true']">
  <pagenode title="{@title}"  url="{@url}"/>
  <xsl:apply-templates/>
 </xsl:template>
</xsl:stylesheet>

then i have 2 problems

  1. i might type out each attribute separately, and i have quite a few per page and theyre apt to change eventually
  2. it loses the hierarchy. everything becomes flat one after the other

i would appreciate all and any help in the matter.

thank you!

EDIT: sample output that id like to see

<pagenode title="home" url="~/" fornavbar="true">
 <pagenode title="events" url="~/admin/events" fornavbar="true"/>
 <pagenode title="catalog" url="~/catalog" fornavbar="true"/>
</pagenode>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-19T11:18:11+00:00Added an answer on May 19, 2026 at 11:18 am

    you can iterate over the attributes of an node using xsl:foreach select="@*"
    this way you don’t have to copy the attributes by hand. if you call xsl:apply-templates
    inside of yor pagenode element you should get the desired result.

    <?xml version="1.0" encoding="ISO-8859-1"?>
    <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
        <xsl:template match="pagenode[@fornavbar='true']">
            <pagenode>
                <xsl:for-each select="@*">
                    <xsl:attribute name="{name(.)}"><xsl:value-of select="."/></xsl:attribute>
                </xsl:for-each>
                <xsl:apply-templates/>
            </pagenode>
        </xsl:template>
    </xsl:stylesheet>
    

    makes

    <?xml version="1.0"?>
    <pagenode title="home" url="~/" fornavbar="true">
        <pagenode title="events" url="~/admin/events" fornavbar="true"/>
      <pagenode title="catalog" url="~/catalog" fornavbar="true"/>
    </pagenode>
    
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