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Home/ Questions/Q 4041024
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T12:49:40+00:00 2026-05-20T12:49:40+00:00

hi i have a situation like this: >>> def get(): … for i in

  • 0

hi i have a situation like this:

>>> def get():
...     for i in range(3):
...             yield [0]
... 

and i want to get this: [0,0,0]

my code now works in this way:

>>> r = []
>>> r.extend(i[0] for i in get())
>>> r
[0, 0, 0]

but i don’t like i[0]..
some advice?

(i’m on python3)

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  1. Editorial Team
    Editorial Team
    2026-05-20T12:49:41+00:00Added an answer on May 20, 2026 at 12:49 pm

    r.extend(i[0] for i in get())

    This kind of imperative code (stateful, with inplace updates) is asking for trouble. That seems the canonical use for a functional flatten (concat):

    from itertools import chain
    
    def flatten(listOfLists):
        return chain.from_iterable(listOfLists)
    
    def get():
        for i in range(3):
            yield [0]
    
    print(list(flatten(get())))
    # [0, 0, 0]
    
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