Question

Hi I have a string “72\n” When I try to use Integer.parseInt(“72\n”) it gives me a log error, unable to parse’72 ‘ as integer. What can I do to filter out the \n?

Thanks

Answer 1

replaceAll with an appropriate regex should work well. For instance \\D will find all non-numeric characters, and so myString.replaceAll("\\D", "") could work well:

  String test2 = "72\n";      
  System.out.printf("\"%s\"%n", test2);

  test2 = test2.replaceAll("\\D", "");
  System.out.printf("\"%s\"%n", test2);

This gets trickier if we allow for non-int floating point numbers which allow for locale dependent non-numeric chars such as a single . for a decimal point in the usa and , in some other locations.