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Editorial Team
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Asked: 2026-06-13T07:10:11+00:00

Hi I have a structure as follows. The issue is once the error message

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Hi I have a structure as follows. The issue is once the error message is displayed, the text box content disappears and need to re-type a value again. I need to retain the original text box value/content as it is whilst the message is displayed. How do you think I should change? Thanks.

    <?php 
if(isset($_POST['subN'])) {
$InNo = $_POST['invc_no'];

$MSG = '';
if($InNo == "") 
{$MSG = 'Invoice number is required';} 
else
{//some code to save data to a database}
?>

<!DOCTYPE html>
<head><title></title></head>
<body>
<form method="POST" action="<?php echo $_SERVER['PHP_SELF']; ?>">
<div id="msgBox"><?php if(!empty($MSG)) echo $MSG; ?></div>
<table>
<tr>
<td><input type="text" id="invc_no" name="invc_no" size="15" class="colr" value="<?php htmlentities('InNo')?>"></td>
<td><input type="submit" name="subN" id="subN" value="Save"></td>
</tr>
</table>
</form>
</body>
</html>
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1 Answer

  1. Editorial Team

    Change

    <input type="text" id="invc_no" name="invc_no" size="15" class="colr" value="<?php htmlentities('InNo')?>">

    To

    <input type="text" id="invc_no" name="invc_no" size="15" class="colr" value="<?php echo htmlentities($_POST['invc_no'])?>">

    Second Solution:

    Put as below

    $InNo = ''; // if you doesn't put any value into text box, then you will get undefined error while you use this variable later on so give initial value to null

if(isset($_POST['subN'])) {
 continue ....
}
else{
 continue ..
}

<input type="text" id="invc_no" name="invc_no" size="15" class="colr" value="<?php echo htmlentities($InNo); ?>">
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