Question

Hi, I have an array and I want to pass a variable to a function.

'#\@(.*?)\;#si' =>  'some before text' . retrieveName('$1') . 'some after text,'

function retrieveName($poster_id){
    $sanitized_id = sanitizeIn($poster_id);

    $getname = mysql_query("SELECT * FROM users WHERE userid = '$sanitized_id';") 
                or die(mysql_error());
    $namerow = mysql_fetch_array($getname);
    $exists = mysql_num_rows($getname);

    if($exists == "0"){
      return $sanitized_id;
    } else {
      return $namerow['username'];
    }
}

It’s supposed to take the value of $1, check the database for a user with that id, then return their username. But no parameter is being passed to retrieveName

Answer 1

The retrieveName function should read:

function retrieveName($poster_id){
    $sanitized_id = sanitizeIn($poster_id);
    $get_name = mysql_query("SELECT * FROM users WHERE userid = '$sanitized_id';") or die(mysql_error());
    $name_row = mysql_fetch_array($get_name);
    return $name_row['username'];
}

I strongly advise on placing some error checking there though, what happens if the ID is not found?

Edit:

if you’re trying to do a “preg_replace templating”, then the line should read:

'#@(.*?);#sie' =>  '"some before text".retrieveName("\1")."some after text"',

‘e’ in the modifiers to execute the code.

This should change, e.g., “Hello, @lserni;, how goes?” with “Hello, some before textLeonardo Sernisome after text, how goes?”.