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Home/ Questions/Q 6018171
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Editorial Team
  • 0
Editorial Team
Asked: May 23, 20262026-05-23T03:14:11+00:00 2026-05-23T03:14:11+00:00

Hi I have this script: function ajax(){ if (navigator.standalone) return; for (var i= document.links.length;

  • 0

Hi I have this script:

function ajax(){
    if (navigator.standalone) return;
    for (var i= document.links.length; i-->0;) {
        document.links[i].onclick= function() {
            var req= new XMLHttpRequest();
            req.onreadystatechange= function() {
                if (this.readyState!==4) return;
                document.body.innerHTML= this.responseText;
                ajax();
            };
            req.open('GET', this.href, true);
            req.send();
            return false;
        };}
    }



window.onload= function() {
    window.scrollTo(0, 0.9);
    ajax();

};

Now I just want to add 1 little thing. If a link has a class called “noeffect” the ajax should not execute (annother page should load).I’ve tried something but i Am just not good enough with javascript to get this right:

function ajax(){
    if (navigator.standalone) return;
    for (var i= document.links.length; i-->0;) {
        if (document.links[i].getAttribute("class") == "noeffect") return;
        document.links[i].onclick= function() {
            var req= new XMLHttpRequest();
            req.onreadystatechange= function() {
                if (this.readyState!==4) return;
                document.body.innerHTML= this.responseText;
                ajax();
            };
            req.open('GET', this.href, true);
            req.send();
            return false;
        };}
    }



window.onload= function() {
    window.scrollTo(0, 0.9);
    ajax();

};

I guess it checkes all links instead of each one but I don’t know how to code this the right way. :s

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T03:14:11+00:00Added an answer on May 23, 2026 at 3:14 am

    Figured it out!

    function ajax(){
        if (navigator.standalone) return;
        for (var i= document.links.length; i-->0;) {
            document.links[i].onclick= function() {
                if(this.getAttribute("class") == "noeffect") return;
                var req= new XMLHttpRequest();
                req.onreadystatechange= function() {
                    if (this.readyState!==4) return;
                    document.body.innerHTML= this.responseText;
                    ajax();
                };
                req.open('GET', this.href, true);
                req.send();
                return false;
            };}
        }
    
    
    
    window.onload= function() {
        window.scrollTo(0, 0.9);
        ajax();
    
    };
    
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