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Home/ Questions/Q 7947319
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T01:23:51+00:00 2026-06-04T01:23:51+00:00

Hi i have this simple code: var datastring=123; $.ajax({ url: ‘actualizarimagen.php’, type: ‘post’, dataType:

  • 0

Hi i have this simple code:

var datastring="123";
$.ajax({ 
        url: 'actualizarimagen.php',
        type: 'post',
        dataType: 'text',
        data: datastring,
        cache: false,
        success: function(response){
            $('.msg1').html(response);

         },
        error: function(response){
            $('.msg1').html(response);
         }

    });

And in actualizarimagen.php:

$desc_larga = print('<pre>') & print_R($_POST) & print('</pre>');
$insertSQL = sprintf("INSERT INTO prueba (texto) VALUES ($desc_larga)");

I get the success message, but in the database always saves 1. I tried changing everything, the dataType, the success, error, complete functions but it doesn’t work. I was searching but any answers couldn’t help me.

Thanks.

Edit: Added response

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  1. Editorial Team
    Editorial Team
    2026-06-04T01:23:52+00:00Added an answer on June 4, 2026 at 1:23 am

    Your datastring should contain data encoded as application/x-www-form-urlencoded

    e.g.: var datastring="foo=123";

    It is better not to pass a string to jQuery at all. Pass it an object and let it handle the encoding for you.

    e.g.: data: { "foo": "123" }

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