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Home/ Questions/Q 4321894
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T08:48:15+00:00 2026-05-21T08:48:15+00:00

HI, I have this string: 2010-12-27 23:05:36.0. When I parse it with CDate like

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HI,

I have this string: “2010-12-27 23:05:36.0”. When I parse it with CDate like this: CDate(“2010-12-27 23:05:36.0”) it returns error 13.
When I remove the ‘.0’ from the string it is working fine.

The date string comes from a database where there is a mixture of dates formatted like this: ‘yyyy-mm-dd’ and ‘yyyy-mm-dd hh-MM-ss.n’ What would be the easy way to get rid of the error 13?

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  1. Editorial Team
    Editorial Team
    2026-05-21T08:48:16+00:00Added an answer on May 21, 2026 at 8:48 am

    You could check the string length -> if it is >19, get rid of the rest and apply then the CDate function

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