Question

Hi i need to open a python script using GUI. Is that possible to give the file path as command to the button? I tried with the below code, but it is showing No such file or directory. Please help
Thank you

import xlwt
from Tkinter import *            
from tkFileDialog   
import askopenfilename      

def callback():
    filename = ('C:\python\abc.py')
    execfile(filename)

abc= Button(text='abc', command=callback)
abc.pack()
mainloop()

Answer 1

The backslash is the escape character, so you should escape it to make it mean “backslash the character” and not “backslash the escape character”. Try assigning filename like this:

filename = ('C:\\python\\abc')