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Home/ Questions/Q 8708809
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T04:13:24+00:00 2026-06-13T04:13:24+00:00

Hi I think this is just a syntax problem, but I might be doing

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Hi I think this is just a syntax problem, but I might be doing something PHP isn’t designed to do.

I’m trying to draw an HTML table, using an array to populate the table. The headers for example.

Where $headers is an array of headers I have attempted:

$html_table = '
                <table border="1" cellspacing="0" cellpadding="2">
                    <tr>
                        foreach($headers as $header)
                        {
                        echo "<th> $header </th>";                          
                        }
                    </tr>
';

The idea being to generate:

 <table border="1" cellspacing="0" cellpadding="2">
    <tr>
        <th>Heading 1</th>
        <th>Heading 2</th>
        <th>Heading 3</th>
        ...
        <th>Heading 99</th>
    </tr>

Simply by later asking for
$html_table

Suffice is to say at the moment I get a single headed column with “$header” in it, becuase the loop is not running inside the variable equation.

The reason I’m storing the HTML as a variable like this is because I want to concatenate (usage?) it with other generated html, i.e.

$html_table .= '</table>';

later on (of course the actual bit in the middle is more complicated, to do with retreiving data from databases to populate the table.

Where am I going wrong? Thanks

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  1. Editorial Team
    Editorial Team
    2026-06-13T04:13:26+00:00Added an answer on June 13, 2026 at 4:13 am

    take the foreach out of the quotes

    $html_table = '
                <table border="1" cellspacing="0" cellpadding="2">
                    <tr>';
    foreach($headers as $header){
        $html_table .= "<th> $header </th>";                          
    }
    $html_table .='
                    </tr>
    ';
    
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