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Home/ Questions/Q 8597083
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T00:50:00+00:00 2026-06-12T00:50:00+00:00

Hi i want to save many different csv files from a function with a

  • 0

Hi i want to save many different csv files from a function with a naming convention based on a different double value. I do this with a for loop and pass a string value to save each .csv file differently. Below is an example of what I’m trying to do the desired result would be

1.1_file.csv
1.2_file.csv

but instead i get

1.1_file.csv
1.11.2_file.csv

Here is a working sample code, what can i do to fix this

#include <sstream>
#include <iomanip>
#include <cmath>
#include <iostream>
#include <vector>

int main(){
    std::string file = "_file.csv";
    std::string s;
    std::ostringstream os;
    double x;

    for(int i = 0; i < 10; i++){
        x = 0.1 + 0.1 *i;
        os << std::fixed << std::setprecision(1);
        os << x;
        s = os.str();
        std::cout<<s+file<<std::endl;
        s.clear();
    }

    return 0;
}
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  1. Editorial Team
    Editorial Team
    2026-06-12T00:50:01+00:00Added an answer on June 12, 2026 at 12:50 am

    The ostringstream doesn’t reset on each iteration of the loop, so you are just adding x to it every iteration; put it inside the scope of the for to make os be a different clean object on each iteration, or reset the contents with os.str("").

    Also, the variable s is unnecessary; you can just do

    std::cout << os.str() + file << std::endl;
    

    And you don’t need s and you eliminate the overhead of making a copy of the string.

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