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Home/ Questions/Q 5934763
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T15:09:34+00:00 2026-05-22T15:09:34+00:00

Hi I’m using pugixml to process xml documents. I iterate through nodes using this

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Hi
I’m using pugixml to process xml documents. I iterate through nodes using this construction

 pugi::xml_node tools = doc.child("settings");

    //[code_traverse_iter
    for (pugi::xml_node_iterator it = tools.begin(); it != tools.end(); ++it)
    {
        //std::cout << "Tool:";
        cout <<it->name();

    }

the problem is that it->name() returns pugi::char_t* and I need to convert it into std::string. Is it possible ?? I can’t find any information on pugixml website

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-22T15:09:35+00:00Added an answer on May 22, 2026 at 3:09 pm

    According to the manual, pugi::char_t is either char or wchar_t, depending on your library configuration. This is so that you can switch between single bytes (ASCII or UTF-8) and double bytes (usually UTF-16/32).

    This means you don’t need to change it to anything. However, if you’re using the wchar_t* variant, you will have to use the matching stream object:

    #ifdef PUGIXML_WCHAR_MODE
    std::wcout << it->name();
    #else
    std::cout << it->name();
    #endif
    

    And, since you asked, to construct a std::string or std::wstring from it:

    #ifdef PUGIXML_WCHAR_MODE
    std::wstring str = it->name();
    #else
    std::string str = it->name();
    #endif
    

    Or, for always a std::string (this is rarely what you want!):

    #ifdef PUGIXML_WCHAR_MODE
    std::string str = as_utf8(it->name());
    #else
    std::string str = it->name();
    #endif
    

    Hope this helps.

    Source: A cursory glance at the “pugixml” documentation.

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