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Home/ Questions/Q 953467
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T00:03:21+00:00 2026-05-16T00:03:21+00:00

Hi I’ve been coding a console version of Minesweeper just to learn some of

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Hi I’ve been coding a console version of Minesweeper just to learn some of the basics of Python. It uses a coordinate system that is recorded in a dictionary. Now, I have been able to implement it successfully but accessing or assigning a value to a specific coordinate key using variables for the “x,y” of the coordinate seems… clunky. There are two different ways that I’ve come up with but they don’t seem very elegant when I have to use them so often.

for i in range(1, ROWS+1):
        for j in range(1, COLS+1):
            mine_field["%i,%i" % (i,j)] = 0

or

for i in range(1, ROWS+1):
        for j in range(1, COLS+1):
            mine_field[",".join([i, j])] = 0

It works well enough but it does start to look messy when assigning or swapping values. Is there a better way that this can be done?

Thanks in advance.

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  1. Editorial Team
    Editorial Team
    2026-05-16T00:03:22+00:00Added an answer on May 16, 2026 at 12:03 am

    Why not simply use a tuple as the key?

    for i in range(1, ROWS+1):
        for j in range(1, COLS+1):
            mine_field[(i, j)] = 0 # you don't even need the parentheses!
    

    Using this method, you can use comma-separated indices like so:

    d = {(1,2):3}
    print d[1, 2] # will print 3
    

    And BTW why are you using one-based indices?

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