Question

Hi lets say I have a table like this:

________________________________________________________
|
|    id     |     order    |  date   |  item  |   price|
-------------------------------------------------------
|     1            1st        date       i1       10,00|
|-------------------------------------------------------    
|     2            2nd       date        u2       15,00|
|-------------------------------------------------------
|     3            1st       date        i1       20,00|
|------------------------------------------------------- 
|     4            2nd       date        u2       30,00|
|-------------------------------------------------------

I need to get total sum of items containing same order name and print DISTINCT orders like:

order_name – date – total sum. or better way to create new tabel and store there total sum of each order and in this table add sum id in each row?

Answer 1

This will literally return order_name - date - total sum, assuming your date column is date

SELECT CONCAT(order, " - ", date, " - ", SUM(price)) as Result
FROM orders
GROUP BY `order`

To add a quantity, try this:

SELECT CONCAT(order, " - ", date, " - ", CASE WHEN quantity > 1 THEN (quantity * SUM(price)) ELSE SUM(price) END) as Result
FROM orders
GROUP BY `order`