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Home/ Questions/Q 7696573
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T21:48:42+00:00 2026-05-31T21:48:42+00:00

Hi my jQuery callback function does not work. Competitor = { addCompetitorForSave: function($data) {

  • 0

Hi my jQuery callback function does not work.

 Competitor = {
    addCompetitorForSave: function($data) {

            $.post('/competition/add', $data , function($json) {

            }, 'json');

           return $json; // I need to return json data .
        }
}

after this I need to do next .

 var data  = $('someForm').serialize();
 var $json  = Competition.addCompetitorForSave(data);

Thanks a lot.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-31T21:48:44+00:00Added an answer on May 31, 2026 at 9:48 pm

    The post completes asynchronously but the alert runs synchronously. Hence the qa value hasn’t been set yet. Instead of return a value here you need to pass an additional callback into addCompetitorForSave.

    addCompetitorForSave: function($data, callback) {
      var qa  = 0;
      $.post('/competition/add', $data , function($json) {
        callback($json);
      }, 'json');
    }
    
    var obj = ...;
    obj.addCompetitorForSave(theData, function(qa) {
      alert(qa);
    });
    
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