Question

hi so im using python and i’m trying to create a function that lets me generate words made up of 2 letters. i also want to count how many of the words generated are actually in the dictionary.

this is what i have so far:

alphabet = ('a','b','c','d','e','f','g','h','i','j','k','l','m','n','o',
            'p','q','r','s','t','u','v','w','x','y','z')
count1 = 0
text = " "

def find2LetterWords():
    for letter in alphabet:
        text += letter
        for letter in alphabet:
            text +=letter
    print text

this is the code i have written so far and i know its not right. i was just experimenting. so yea it would be great if u could help me out. thx.

Answer 1

Answer edited based on comments:

def find2LetterWords():
     #this generates all possible 2-letter combos with a list comprehension
     words = [first + second for second in alphabet for first in alphabet]
     #create a new list with only those words that are in your_dictionary (a list)
     real_words = [word for word in words if word in your_dictionary]
     return real_words

If you want a nice one liner, with no function:

[word for word in [first + second for second in alphabet for first in alphabet] if word in your_dictionary]

Obviously, replace your_dictionary with whatever the name of your dictionary is.