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Home/ Questions/Q 8576783
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T20:00:15+00:00 2026-06-11T20:00:15+00:00

Hi there I’m really struggling getting the following sql query to work, i apologise

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Hi there I’m really struggling getting the following sql query to work, i apologise in advance if ive made a mash of this but im still learning the full advanced areas of SQL.

Here is my code…

"SELECT *,(((acos(sin((".$latitude."*pi()/180)) * 
sin((`latitude`*pi()/180))+cos((".$latitude."*pi()/180)) * 
cos((`latitude`*pi()/180)) * cos(((".$longitude."- `longitude`)*pi()/180))))
*180/pi())*60*1.1515) as distance 
FROM `locations`  l HAVING distance <= '".$distance."' JOIN 
(SELECT * users) u
ON (l.id = u.basic_location)
            WHERE u.id != A $AND2
            ORDER BY distance ASC"

I keep getting the following error message…

You have an error in your SQL syntax; check the manual that corresponds to your 
MySQL server version for the right syntax to use near 
'JOIN (SELECT * users) u ON (l.id = u.basic_location) WHERE u.id' at line 1

Ive tried many combinations of this but ive become stumped and was looking for some help?

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  1. Editorial Team
    Editorial Team
    2026-06-11T20:00:16+00:00Added an answer on June 11, 2026 at 8:00 pm
    1. JOIN should follow right after FROM tablename or another JOIN
    2. You should use WHERE, not HAVING in this case
    3. You should JOIN users u, not subquery (in this case it makes no sense)
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