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Home/ Questions/Q 4087750
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T18:53:40+00:00 2026-05-20T18:53:40+00:00

Hi this may be unusual, but I need to expand this code to a

  • 0

Hi this may be unusual, but I need to expand this code to a more readable form so I can undertsand what it’s doing, then I can maybe expand on the code to make it do what I need it to do. Here’s the code: in full (taken from here)

$(function(){

 // Bind an event to window.onhashchange that, when the hash changes, gets the
 // hash and adds the class "selected" to any matching nav link.
 $(window).hashchange( function(){
   var hash = location.hash;

// Set the page title based on the hash.
document.title = 'The hash is ' + ( hash.replace( /^#/, '' ) || 'blank' ) + '.';

// Iterate over all nav links, setting the "selected" class as-appropriate.
$('.article a').each(function(){
  var that = $(this);
  that[ that.attr( 'href' ) === hash ? 'addClass' : 'removeClass' ]( 'selected' );
});
})

// Since the event is only triggered when the hash changes, we need to trigger
// the event now, to handle the hash the page may have loaded with.
$(window).hashchange();

});

The specific line I dont understand is this one:

  that[ that.attr( 'href' ) === hash ? 'addClass' : 'removeClass' ]( 'selected' );

This is just unreadable to me at my stage of development. I’d like to learn though.
I mean, i get what it’s doing 100%… but i dont know how to affect the parent of “that” with this kind of code, I dont know where i’d put “parent”?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-20T18:53:40+00:00Added an answer on May 20, 2026 at 6:53 pm

    This

    that[ that.attr( 'href' ) === hash ? 'addClass' : 'removeClass' ]( 'selected' );
    

    is a horrible line of code which uses the ternary (?:) operator to pick a function to call.

    In long hand it would be:

    if (that.attr('href') === hash) {
        that.addClass('selected');
    } else {
        that.removeClass('selected');
    }
    

    The original code takes advantage of the fact that

    • $(this).foo is the same as $(this)[foo], so
    • that.foo is the same as that[foo], so
    • that.foo(args) is the same as that[foo](args)

    and then to further complicate things, they made foo a conditional expression!

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