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Home/ Questions/Q 985695
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T05:12:13+00:00 2026-05-16T05:12:13+00:00

Hii , I have been trying to write a program… We have a structure

  • 0

Hii ,

I have been trying to write a program… We have a structure which has a rank field and the name field.The pointer to this structure is stored in an array of fixed size. I have implemented it as follows and i have certain problems…
The code i have written is :

 #include<stdio.h>
#include<stdlib.h>
#include<malloc.h>

typedef struct 
{
 int rank;
 char *name;
}node;

int insert(node **a , char name[] , int *rank)
 {
 if(*rank >= 5)
  {
   printf("\n Overflow ");
   return 0;
  } 
  (*rank)++;
  node *new = (node *)malloc(sizeof(node));
  new->name = name;
  new->rank = *rank;
  a[*rank] = new;

  return 0;
 } 

int delete(node **a , int *rank)
 {
  int i = *rank;
  if(*rank<0)
   {
    printf("\n No elements");
    return 0;
   }
   printf("\n Deleting %d , %s ",((a[*rank]))->rank,((a[*rank]))->name);
   printf("\n Reordering the elements ");
   while(i<5)
    {
     a[i] = a[i+1];
    }  
  return 0;
 }

 int display(node **a , int rank)
  {
   while(rank>0 && (a[rank])>0)
    {
     printf(" rank = %d    name = %s \n",((a[rank])->rank),((a[rank])->name));
     rank--;
    }            
    return 0;
  }

int main()
 {
  node *a[5] = {NULL};
  char ch = 'y';
  int choice,rank = -1;
  char name[10];
  while(ch!='n' || ch!= 'N')
   {
    printf("\n Enter 1 to insert , 2 to delete , 3 to display and 4 to exit \n");
    scanf("%d",&choice);
    switch(choice)
     {
      case 1:
        printf("\n Enter name to insert");
        gets(name);
        insert(a,name,&rank);
        break;
      case 2:
        printf("\n Enter rank to delete ");
        scanf("%d",&rank);
        delete(a,&rank);
        break;
      case 3:
        display(a,rank);
        break;
      case 4:
        exit(0);
      default:
        printf("\n Invalid choice...please enter again ");
        break;
     } 
    ch = getchar();
  }
 return 0;
 } 

First thing is the system automatically takes the choice except for the first time…(i couldn’t find the fault there…) and i am a bit confused about this pointer stuff…Please see if its alright…Any corrections are welcome and please give me some explanation as to why it is wrong and how we shd do it…

Thank You

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T05:12:13+00:00Added an answer on May 16, 2026 at 5:12 am

    First of all, all your functions always return 0 — even for an error condition. Life would be so much easier, if you passed rank in as an int, and returned it’s new value.

    rank = insert(a, name, rank); 
    /* : */
    /* : */
    int insert(node **a , char name[] , int rank)  
    {  
     if(rank >= 5)  
     {  
       printf("\n Overflow ");  
       return 0;  
     }   
     rank++;  
     node *new = (node *)malloc(sizeof(node));  
     new->name = name;  
     new->rank = rank;  
     a[rank] = new;  
     return rank;  
    }
    

    It’s been many years since I last used scanf, but as I recall, you must account for every character in the stream, meaning,”Don’t forget the Enter”.

    scanf("%d\n",&choice);  
    

    Also with gets(name);, if you type more tha 9 characters, you are quite screwed, as it will overwrite the stack of your program.

    UPDATE:
    Also, you have two ways to exit this program, except one will never work. You could choose option “4” which will call exit(0). Alternately, at the end of each command, you wait for a character before stepping over. It appears you want to be able to enter “N” ther and exit, except that won’t work:

    while(ch!='n' || ch!= 'N') 
    

    for that to evaluate to false, ch must be both “n” & “N” at the same time. You really want

    while(ch!='n' && ch!= 'N') 
    

    UPDATE2:
    I just noticed the biggest problem in you code. name everywhere in your code only ever points to the single array defined in main(). Everytime you enter a new name, it overwrites that array, and since every node points to that one array, the name changes everywhere. You need to make a copy.
    in insert():

    node *new = (node *)malloc(sizeof(node));     
    new->name = strdup(name);    // use malloc internally.
    

    Then in delete() you’ll have to free that memory (speaking of which, you need to free node there too…)

    printf("\n Deleting %d , %s ",((a[*rank]))->rank,((a[*rank]))->name);       
    free(a[*rank]->name);
    free(a[*rank]);
    printf("\n Reordering the elements ");
    

    Remember, Whenever you call malloc, you will eventually have to call free.

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