Question

How are unicode comparisons coded? I need to test exactly as below, checking for specific letters in a string. The code below chokes: warning: comparison between pointer and integer

for (charIndex = 0; charIndex < [myString length]; charIndex++)
{
   unichar testChar = [myString characterAtIndex:charIndex];

     if (testChar == "A")  
       // do something
     if (testChar == "B")
      // do something
     if (testChar == "C")
      // do something
}

Answer 1

For char literals, use single quotes:

if (testChar == 'A') NSLog(@"It's an A");

Or represent the character using the code point number:

if (testChar == 0x1e01) NSLog(@"It's an A with a ring below");

The compiler sees double-quotes as a string, so builds “A” as equivalent to a const char * (which gives you there error message about the pointer).