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Home/ Questions/Q 6856343
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T01:52:25+00:00 2026-05-27T01:52:25+00:00

How can I access an Android resource using RandomAccessFile in Java? Here is how

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How can I access an Android resource using RandomAccessFile in Java?

Here is how I would like this to work (but it doesn’t):

String fileIn = resources.getResourceName(resourceID);
Log.e("fileIn", fileIn);
//BufferedReader buffer = new BufferedReader(new InputStreamReader(fileIn));

RandomAccessFile buffer = null;
try {
  buffer = new RandomAccessFile(fileIn, "r");
} catch (FileNotFoundException e) {
  Log.e("err", ""+e);
}

Log output:

fileIn(6062): ls3d.gold.paper:raw/wwe_obj

The following exception appears in my console:

11-26 15:06:35.027: ERROR/err(6062): java.io.FileNotFoundException: /ls3d.gold.paper:raw/wwe_obj (No such file or directory)
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T01:52:25+00:00Added an answer on May 27, 2026 at 1:52 am

    I’m using this code:

    public static String readContentFromResourceFile(Context context, int resourceId)
    throws IOException {
        StringBuffer sb = new StringBuffer();
        final String NEW_LINE = System.getProperty("line.separator");
    
        InputStream is = context.getResources().openRawResource(resourceId);
        BufferedReader br = new BufferedReader(new InputStreamReader(is));
        String readLine = null;
    
        try {
            while ((readLine = br.readLine()) != null) {
                sb.append(readLine);
                sb.append(NEW_LINE);
            }
        } catch (IOException e) {
            throw e;
        } finally {
            br.close();
            is.close();
        }
    
        return sb.toString();
    }
    
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