Question

How can I access the first value from

object t = (object) wsf.LinEst(y.ToArray(), x.ToArray(), false, true);

The output is

object[1..5, 1..2]}
    [1, 1]: 0.17134831460674155
    [1, 2]: 0.0
    [2, 1]: 0.019612696690686725
    [2, 2]: -2146826246
    [3, 1]: 0.95020429009193053
    [3, 2]: 0.82746057986828336
    [4, 1]: 76.328205128205056
    [4, 2]: 4.0
    [5, 1]: 52.261235955056179
    [5, 2]: 2.7387640449438226

I need to get only [1,1] ‘s value i.e. 0.17134831460674155

How to get that.

The linEst return an object only.

I am using C#3.0

Thanks

Thanks

Answer 1

Well, it looks like it’s something you can enumerate which returns doubles – although it may not actually implement IEnumerable<double>. Try this (with a using System.Linq; directive at the top of your code):

IEnumerable t = (IEnumerable) wsf.LinEst(y.ToArray(), x.ToArray(), false, true);
double first = t.Cast<double>().First();

However, that won’t work if actually it’s returning something like an int[][]. Could you tell us more about what it’s really returning? Yes, it’s declared to just return object, but it’s clearly returning something more than that. If you know it will always return an object[,] with 1-based indexes, you could cast to that:

object[,] t = (object[,]) wsf.LinEst(y.ToArray(), x.ToArray(), false, true);
double first = (double) t[1, 1];

If you don’t know the lower bounds of the array, you can ask for them programmatically of course… but the LINQ way will probably be simpler.