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Home/ Questions/Q 8638897
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T10:51:25+00:00 2026-06-12T10:51:25+00:00

How can I access the name of the file in below scala code :

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How can I access the name of the file in below scala code :

object FileMatcher {

  private def filesHere = (new java.io.File("c:\\")).listFiles

  def filesEnding(query: String) = 
    for (file <- filesHere; if file.getName.endsWith(query))
      yield file.getName

  def main(args: Array[String]) {
      println(filesEnding(".js"))  
    }

}

I have one .js file and the output is : [Ljava.io.File;@df8f5e

I have tried changing ‘yield file’ to ‘yield file.getName’ but same result.

I’m assuming println(filesEnding(“.js”)) calls the toString method of whatever the def ‘filesEnding’ yields, is this correct ?

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  1. Editorial Team
    Editorial Team
    2026-06-12T10:51:27+00:00Added an answer on June 12, 2026 at 10:51 am

    filesEnding yields an Array[String] (when you use yield file.getName and Array[File] when you use yield file) the toString method of Array, is the default toString implementation. which is the hash code printed… and this is exactly what you’re getting. you probably meant println(filesEnding(".js").mkString("\t","\n\t","\n")) which should print your files nicely.

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