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Home/ Questions/Q 8024423
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T22:52:07+00:00 2026-06-04T22:52:07+00:00

how can I add custom control on the basis of sessionScope variable. I try

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how can I add custom control on the basis of sessionScope variable. I try include page container control but no luck:

<xp:this.afterPageLoad><![CDATA[#{javascript:sessionScope.put("viewName","ccViewAll.xsp");}]]></xp:this.afterPageLoad>
<xp:text escape="true" id="computedField1">
    <xp:this.value><![CDATA[#{javascript:sessionScope.get("viewName")}]]></xp:this.value>
</xp:text>
<xc:appLayout>
    <xp:this.facets>
        <xp:panel xp:key="facetMiddle">
            <xp:include id="include1">
                <xp:this.pageName><![CDATA[${javascript:sessionScope.get("viewName")}]]>
                </xp:this.pageName>
            </xp:include>
        </xp:panel>
    </xp:this.facets>
</xc:appLayout>

The above code give me error Error 404 HTTP Web Server: Item Not Found Exception. But when I hardcode the viewname that is ccViewAll.xsp instead of sessionScope.get(“viewName”), its work fine.

-MAK

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  1. Editorial Team
    Editorial Team
    2026-06-04T22:52:08+00:00Added an answer on June 4, 2026 at 10:52 pm

    If you are using this to show a different view in the domino database based on some other selection that I would suggest looking at the Extension Libraries ‘Dynamic View Panel’ control.

    Using this control means you won’t need to create different custom controls for each view that you want to use, just a single page with this control and point it to the correct view to display via a scope variable.

    If you need to customize how each view displays you can create a viewControl bean to set additional properties based on the view that it is showing.

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