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Home/ Questions/Q 888937
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T13:29:08+00:00 2026-05-15T13:29:08+00:00

How can I add letter to path? For example if i have a path

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How can I add letter to path?

For example if i have a path like 'c:\example2\media\uploads\test5.txt' (stored in a variable), but I need something like r'c:\example2\media\uploads\test5.txt', how can I add letter `r?

Because the function open() does not want to open the first path. When I try add path to function open() it gives me an error and path like this: u'c:\\example2\\media\\uploads\\test5.txt' and says that file or directory is absent. What should i do?

Error looks like:

[Error 3] The system cannot find the path specified: u'C:\\example2\\media\\upload\\ZipFile.zip'

when i do this open(‘c:\example2\media\uploads\test5.txt’) it not work. And gives me error ( which you can see on the top)

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  1. Editorial Team
    Editorial Team
    2026-05-15T13:29:09+00:00Added an answer on May 15, 2026 at 1:29 pm

    From the error message it is clear that the string is stored in the correct format (backslashes are escaped by doubling). So it seems the path is wrong, and the file is indeed absent.

    On the other hand, in your second example that you added in your edit, you use open('c:\example2\media\uploads\test5.txt') – this will definitely fail because \t is a tab character (whereas all the other backslash-letter combinations don’t exist, so the backslash will be treated like it was escaped correctly). But you said that the string was stored in a variable, so I don’t see how this example helps here.

    Consider the following:

    >>> path = 'c:\example2\media\uploads\test5.txt'
    >>> path
    'c:\\example2\\media\\uploads\test5.txt'
    

    See? All the backslashes are converted to escaped backslashes except for the \t one because that’s the only one with special meaning. And now, of course, this path is wrong. So if the variables you’re referring to have been defined this way (and now contain invalid paths) there’s not much you can do except fix the source:

    >>> path = r'c:\example2\media\uploads\test5.txt'
    >>> path
    'c:\\example2\\media\\uploads\\test5.txt'
    

    You might think you could “fix” a defective path afterwards like this:

    >>> path = 'c:\example2\media\uploads\test5.txt'
    >>> path.replace("\t","\\t")
    'c:\\example2\\media\\uploads\\test5.txt'
    

    …but there are many other escape codes (\b, \r, \n etc.), so that’s not really a feasible way, especially because you’d be doctoring around the symptoms instead of fixing the underlying problem.

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