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Home/ Questions/Q 7413317
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T06:40:36+00:00 2026-05-29T06:40:36+00:00

How can I add precision to drand48() in C++? I am using it in

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How can I add precision to drand48() in C++?
I am using it in a function like:

double x = drand48()%1000+1;

to generate numbers below 1000.
But then I get this error:

error: invalid operands of types ‘double’ and ‘int’ to binary ‘operator%’

This does not happen when I use:

double x = rand()%1000+1;

Why and what is the difference between rand() and drand48()?

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  1. Editorial Team
    Editorial Team
    2026-05-29T06:40:38+00:00Added an answer on May 29, 2026 at 6:40 am

    drand48 returns a double in the range of 0.0 to 1.0. You want to multiply that by the range you’re looking to generate. double x = drand48() * 1000.0

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