Question

How can i break parent if in PHP?

example this code:

if(true){ // This is parent conditional
    if(true) { // This is child conditional
        break parent conditinal
    }
}

afterBreakDoMe();

From code above. I want when child conditional is true. Then it break parent conditional (exit from that conditional) and continue the rest of the code (afterBreakDoMe()).

Update – Real code

    $errorMessage = '';
    if(isset($_POST) && count($_POST)) { // Detect some user input
        // validation
        $countryName = trim($_POST['countryName']);         
        if($countryName == ''){ // validation user input, if false. exit from parent if and continue show html input (refer to $Render->output())
            $errorMessage = 'Name must not be empty!'; 
        }

        header('Location: '.$baseUrl.'&page=tableShipping');
    }

    $Render->setTitle('Create New Country');
    $form = $Render->parser('createCountry', array(
        'errorMessage' => $errorMessage,
    ));
    $Render->addContent($form);

    $Render->output();

Answer 1

You could use a variable and an extra if-statement:

$errorMessage = '';
$emptyCountry = false;
if(isset($_POST) && count($_POST)) { // Detect some user input
    // validation
    $emptyCountry = trim($_POST['countryName']) == '';
    if($emptyCountry){ // validation user input, if false.
        $errorMessage = 'Name must not be empty!'; 
    }

    header('Location: '.$baseUrl.'&page=tableShipping');
}
if (!emptyCountry) {
    $Render->setTitle('Create New Country');
    $form = $Render->parser('createCountry', array(
        'errorMessage' => $errorMessage,
    ));
    $Render->addContent($form);
}

$Render->output();