Question

How can I calculate the next day from a string like 20110531 in the same YYYYMMDD format? In this particular case, I like to have 20110601 as the result. Calculating “tomorrow” or next day in static way is not that tough, like this:

>>> from datetime import date, timedelta
>>> (date.today() + timedelta(1)).strftime('%Y%m%d')
'20110512'
>>>
>>> (date(2011,05,31) + timedelta(1)).strftime('%Y%m%d')
'20110601'

But how can I use a string like dt = "20110531" to get the same result as above?

Answer 1

Here is an example of how to do it:

import time
from datetime import date, timedelta

t=time.strptime('20110531','%Y%m%d')
newdate=date(t.tm_year,t.tm_mon,t.tm_mday)+timedelta(1)
print newdate.strftime('%Y%m%d')