Question

How can I can get the char representation of an integer in the range 0 – 9 ?
Given that digit1 is an integer in that range,
I’ve tried

char1 = (char) digit1;
System.out.printf("%s", Character.toString(char1));

and also

char1 = 'digit1';  
System.out.printf("%s", Character.toString(char1));  

But each time it prints a “weird” character whereas I was expecting the corresponding one-digit integer.

Is there something that I’m doing wrong in the printing or somewhere else?
THanks in advance.

Answer 1

You are confusing the value 0 with the ASCII character '0'.

Any of the following would work:

System.out.printf("%d", digit);
System.out.printf("%c", digit + '0');
System.out.printf("%s", Character.toString((char)(digit + '0')));