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Home/ Questions/Q 6704879
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T07:20:22+00:00 2026-05-26T07:20:22+00:00

How can I check if a number has a – , + , x

  • 0

How can I check if a number has a -, +, x or nothing in front of it?

Options to check would be:

20
+20
-20
x20

20 being any number.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T07:20:22+00:00Added an answer on May 26, 2026 at 7:20 am

    If you wanted to be a little more flexible and allow whitespace so you were looking for the first non-whitespace character that comes before a digit, you could use a regular expression:

    var str = " + 20";
    
    var match = str.match(/^\s*([^\d])/);
    if (match) {
        switch(match[1]) {
            case "+":
                // put code here to handle this operator
                break;
            case "-":
                // put code here to handle this operator
                break;
            case "x":
                // put code here to handle this operator
                break;
            default:
                // put code here to handle unknown operator
                break;
        }
    }
    

    Working example here: http://jsfiddle.net/jfriend00/fJcQJ/

    Or, if you wanted a function that would return prefix and number, you could do this:

    function parseNum(str) {
        var match = str.match(/^\s*([\+\-x]?)\s*(\d+)/);
        if (match) {
            return({
                num: parseInt(match[2], 10),
                prefix: match[1] ? match[1] : ""
            });
        }
        // nothing found of the right format
        return(null);
    }
    

    And, a working example with test cases: http://jsfiddle.net/jfriend00/DCxcb/

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