Question

How can I compare two OrderedDict dictionareis?

My structure is the following:

dict_a = OrderedDict([(1,4), (2,5), (3,3), (4,5), (5,4), (6,4), (7,4), (8,3), (9,4)])

dict_b = OrderedDict([(1,4), (2,2), (3,1), (4,4), (5,6), (6,7), (7,4), (8,2), (9,5)])

for values in score_dict.items():
if values == course_dict.values():
    print 'match!'
else:
    print 'No match!'

It iterates through and both lists are ordered so it should match on 1 and 7?
Thanks in advance!

Answer 1

You can use items() and the built-in zip() function:

for i, j in zip(dict_a.items(), dict_b.items()):
    if i == j:
        print(i)

Output:

(1, 4)
(7, 4)