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Home/ Questions/Q 9255655
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T11:45:37+00:00 2026-06-18T11:45:37+00:00

How can I convert a data.frame df <- data.frame(id=c(af1, af2), start=c(100, 115), end=c(114,121)) To

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How can I convert a data.frame

df <- data.frame(id=c("af1", "af2"), start=c(100, 115), end=c(114,121))

To a list of lists

LoL <- list(list(id="af1", start=100, end=114), list(id="af2", start=115, end=121))

I’ve tried things like

not.LoL <- as.list(as.data.frame(t(df)))

and I’m really not sure what I end up with after this, but it isn’t quite right. My requirement is that I can access, say, the first start by the command

> LoL[[1]]$start
[1] 100

the not.LoL that I currently have gives me the following error:

> not.LoL[[1]]$start
Error in not.LoL[[1]]$start : $ operator is invalid for atomic vectors

Explanations and/or solutions would be greatly appreciated.

Edit: I should have made it clear that “id” here is actually non-unique – there can be multiple elements under a single ID. So I could do with a solution that doesn’t depend on unique IDs to split on.

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  1. Editorial Team
    Editorial Team
    2026-06-18T11:45:38+00:00Added an answer on June 18, 2026 at 11:45 am

    Using plyr , you can do this

    dlply(df,.(id),c)
    

    To avoid grouping by id , if there are multiple ( maybe you need to change column name , id is unique for me)

    dlply(df,1,c)
    
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