Question

How can I convert a variable of type var or var* to var&

I’ve to use a function which takes an object of var class(suppose there’s a class). The example code was given like this:-

testFunc(false, namespace1::namespace2::var(), 100);

in function declaration it says that the second parameter is of type namespace1::namespace2::var&, I can create namespace1::namespace2::var or namespace1::namespace2::var*, but how do I create namespace1::namespace2::var&?

I know that’s too basic question but I couldn’t figure it out.

Edit:
I’ve tried using just var, but it gives some odd errors. I am pretty sure that’s some kind of fault in the function I am using. Here’re the errors:-

Error   3   error C2825: 'CType': must be a class or namespace when followed by '::'
Error   4   error C2039: 'TypeCode' : is not a member of '`global namespace''
Error   5   error C2146: syntax error : missing ',' before identifier 'TypeCode'
Error   6   error C2065: 'TypeCode' : undeclared identifier 
Error   7   error C3203: 'CustomType' : unspecialized class template can't be used as a template argument for template parameter 'Base', expected a real type   

Edit 2

I thought it’d be hard to answer if I include real code, since it’s complicated. But have a look if it helps. The real function’s signature is like this:-

virtual bool opRaiseEvent(bool reliable, const Common::Hashtable& parameters, nByte eventCode, nByte channelID=0, int* targetPlayers=NULL, short numTargetPlayers=NULL);

and the example code used the function like this:-

mLoadBalancingClient.opRaiseEvent(false, ExitGames::Common::Hashtable(), 100);

which was working fine. But now I want to add data to the HashTable, so I need to create an object of it and then pass it to the function. It’s not accepting a pointer or normal variable. I don’t know why it’s working with just HashTable().

Answer 1

This should work :

const Common::Hashtable param = namespace1::namespace2::var();
opRaiseEvent(false, param, 100);