Question

How can I create a function that will have a dynamic return type based on the parameter type?

Like

protected DynamicType Test(DynamicType type) {  return ;   } 

Answer 1

You’d have to use generics for this. For example,

protected T Test<T>(T parameter) {  } 

In this example, the ‘<T>‘ tells the compiler that it represents the name of a type, but you don’t know what that is in the context of creating this function. So you’d end up calling it like…

int foo;  int bar = Test<int>(foo);