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Home/ Questions/Q 6078577
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T10:50:58+00:00 2026-05-23T10:50:58+00:00

How can I create an array in shared memory without modifying the kernel using

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How can I create an array in shared memory without modifying the kernel using templates as seen in the official examples. Or is using templates the official way?

In PyOpenCL I can create an array in local memory with setting a kernel argument

kernel.set_arg(1,numpy.uint32(a_width))

... 
KERNEL_CODE = """
__kernel void matrixMul(__local float* A_temp,...)
    { ...} """
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  1. Editorial Team
    Editorial Team
    2026-05-23T10:50:59+00:00Added an answer on May 23, 2026 at 10:50 am

    CUDA supports dynamic shared memory allocation at kernel run time, but the mechanism is a bit different to OpenCL. In the CUDA runtime API, a kernel using dynamically allocated/sized shared memory and the launch to size the memory uses the following syntax:

    __global__ void kernel(...)
    {
        extern __shared__ typename buffer[];
    
        ....
    }
    ....
    kernel <<< griddim, blockdim, sharedmem, streamID >>> (...)
    

    where sharedmem is the total number of bytes per block which will be allocated to buffer.

    In PyCUDA, the same mechanism works something like this:

    mod = SourceModule("""
        __global__ void kernel(...)
        {
            extern __shared__ typename buffer[];
    
            ....
        }
      """)
    
    func = mod.get_function("kernel")
    func.prepare(..., shared=sharedmem)
    func.prepared_call(griddim,blockdim,...)
    

    with the shared memory allocation size passed to the prepare method.

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