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Home/ Questions/Q 8563919
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T17:04:53+00:00 2026-06-11T17:04:53+00:00

How can I define a general function without the exact expression in Mathematica? For

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How can I define a general function without the exact expression in Mathematica? For example, I don’t need this:

a[x_, y_]:= 2x + 3y,

I need to work with a general parameter a(x,y) instead:

a[x_, y_]:= a[x, y].

Of course, this line doesn’t work too well.

Edit1:

Well, I am using the parameter in another unknown function (unknown because it is defined only in the package), which works basically as a derivative, i.e. it’s a very complicated mix of first and second derivatives.

This line

a[x_, y_]:= a[x, y],

actually works (kind of), because the parameter ‘survives’ the package as a function, except in the output I get the annoying “Hold[a[x,y]]” instead of just a[x,y], and I can’t use the result as a function anymore.

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  1. Editorial Team
    Editorial Team
    2026-06-11T17:04:54+00:00Added an answer on June 11, 2026 at 5:04 pm

    The way to “define” a function without specifying an expression is to not define it. Just use it.

    Example:

    D[f[x] g[x],x]
    (*
    ==> g[x] f'[x] + f[x] g'[x]
    *)
    

    As you can see, I didn’t define f or g, and yet Mathematica has no problems calculating with them.

    Note that you can also make definitions using those functions. For example:

    modify[a[x_,y_]]:=a[y,x+y]
    modify[a[2,3]]
    (*
    ==> a[3, 5]
    *)
    

    You can even define arithmetic operations on them. For example, you could define a function exp to symbolically calculate with exponentials (note the lower case, because Exp is already the built-in exponential function), and then define

    exp/: exp[a_] exp[b_] := exp[a+b]
    exp/: exp[a_]^n_Integer := exp[n a]
    

    and then write

    expression = 3 exp[x] exp[y+z]^3
    (*
    ==> 3 exp[x + 3 (y + z)]
    *)
    
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