Question

How can I echo out value after the while loop. If I do the echo in below code its says Undefined index.

$sql_cast = "SELECT *
            FROM
              title_cast
              INNER JOIN title ON (title_cast.id_title = title.id)
              INNER JOIN `cast` ON (title_cast.id_cast = `cast`.id)
            WHERE
              title_cast.id_title = '1'";
$result_cast = mysql_query($sql_cast) or die('log error with' .mysql_error());
$cast = array();
while ($row = mysql_fetch_assoc($result_cast)) {
                $id = $row['id'];
                $name = $row['name'];
                $img = $row['photo_localurl'];
                $poster = str_replace("./", "lib/", $img);

                $cast[] = array('id' => $id, 'name' => $name, 'img' => $poster);
                //$cast[] = $row;
                }
                //var_dump($cast);
                echo $cast['id'] . " " . $cast['name'] . " " . $cast['poster']."<br />";

Answer 1

Within the while loop, you set the cast array content using $cast[] syntax. This will create a numerical index, starting at 0, then 1 and so on, so you’re creating an array that looks like this:

$cast = array(
    0 => array('id' => $id, 'name' => $name, 'img' => $poster),
    1 => array('id' => $id, 'name' => $name, 'img' => $poster)
);

You need to include the numerical key of the array that you want to echo. For example, if you want to echo the first row:

echo $cast[0]['id']; // Echo the id of the first result

If you want to echo ALL of the rows, use foreach:

foreach($cast as $row) {
    echo $row['id'];
}