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Home/ Questions/Q 680261
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T01:21:09+00:00 2026-05-14T01:21:09+00:00

How can I efficiently and easily sort a list of tuples without being sensitive

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How can I efficiently and easily sort a list of tuples without being sensitive to case?

For example this:

[('a', 'c'), ('A', 'b'), ('a', 'a'), ('a', 5)]

Should look like this once sorted:

[('a', 5), ('a', 'a'), ('A', 'b'), ('a', 'c')]

The regular lexicographic sort will put ‘A’ before ‘a’ and yield this:

[('A', 'b'), ('a', 5), ('a', 'a'), ('a', 'c')]
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T01:21:09+00:00Added an answer on May 14, 2026 at 1:21 am

    You can use sort‘s key argument to define how you wish to regard each element with respect to sorting:

    def lower_if_possible(x):
        try:
            return x.lower()
        except AttributeError:
            return x
    
    L=[('a', 'c'), ('A', 'b'), ('a', 'a'), ('a', 5)]
    
    L.sort(key=lambda x: map(lower_if_possible,x))
    print(L)
    

    See http://wiki.python.org/moin/HowTo/Sorting for an explanation of how to use key.

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