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Home/ Questions/Q 780869
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T20:08:32+00:00 2026-05-14T20:08:32+00:00

How can i efficiently display the status of a file when using a background

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How can i efficiently display the status of a file when using a background thread?

For instance, lets say i have a 100MB file:

when i do the code below via a thread (just as an example) it runs in about 1 min:

foreach(byte b in file.bytes)
{
   WriteByte(b, xxx);
}

But… if i want to update the user i have to use a delegate to update the UI from the main thread, the code below takes – FOREVER – literally i don’t know how long im still waiting, ive created this post and its not even 30% done.

int total = file.length;
int current = 0;
foreach(byte b in file.bytes)
{
   current++;
   UpdateCurrentFileStatus(current, total);
   WriteByte(b, xxx);
}

public delegate void UpdateCurrentFileStatus(int cur, int total);
public void UpdateCurrentFileStatus(int cur, int total)
{
        // Check if invoke required, if so create instance of delegate
        // the update the UI

        if(this.InvokeRequired)
        {

        }
        else
        {
          UpdateUI(...)
        }
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T20:08:33+00:00Added an answer on May 14, 2026 at 8:08 pm

    I recommend that you update according to elapsed time so that you have predictable update intervals regardless of file size or system load:

        DateTime start = DateTime.Now;
        foreach (byte b in file.bytes)
        {
            if ((DateTime.Now - start).TotalMilliseconds >= 200)
            {
                UpdateCurrentFileStatus(current, total);
                start = DateTime.Now;
            }
        }
    
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