Question

How can I get a function pointer to the overloaded function that the compiler would choose after inspecting the arguments? In this example:

#include <iostream>

void MyFunction(float a){}
void MyFunction(int a){}

int main()
{
  float a;

  MyFunction(a);

  void (*manualFunctionPointer)(float);
  manualFunctionPointer(a);

  // automaticFunctionPointer = ?
}

I have specified that I want a function pointer to the function that accepts a float and returns void. The compiler can certainly figure that out by itself, because the MyFunction(a) call calls the right function. Is there a way to get a function pointer to the function that the compiler chooses?

Answer 1

Replace the float in

void (*manualFunctionPointer)(float);

With

void (*manualFunctionPointer)(decltype(a));

Then whatever a changes too, manualFunctionPointer will follow