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Home/ Questions/Q 761965
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T15:54:05+00:00 2026-05-14T15:54:05+00:00

How can I implement this fluent interface in C++: class Base { public: Base&

  • 0

How can I implement this fluent interface in C++:

class Base {
public:
  Base& add(int x) {
    return *this;
  }
}

class Derived : public Base {
public:
  Derived& minus(int x) {
    return *this;
  }
}

Derived d;
d.add(1).minus(2).add(3).minus(4);

Current code doesn’t work since Base class doesn’t know anything about Derived class, etc. I would be very thankful for a hint/suggestion.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T15:54:05+00:00Added an answer on May 14, 2026 at 3:54 pm

    Make Base class templated. Use the wanted return type of Base the template type, like this:

    template <typename T>
    class Base {
    public:
      T& add(int x) {
        return *static_cast<T *>(this);
      }
    }
    

    Then inherit Derived from Base like this:

    class Derived : public Base<Derived>
    

    Alternatively (as an answer to Noah’s comment), if you don’t want to change Base, you could use an intermediate class that performs the casting, like this:

    template <typename T>
    class Intermediate : public Base {
    public:
      T& add(int x) {
        Base::add(x);
        return *static_cast<T *>(this);
      }
    }
    

    And let Derived inherit from Intermediate:

    class Derived : public Intermediate<Derived>
    
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