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Home/ Questions/Q 8618685
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T06:10:12+00:00 2026-06-12T06:10:12+00:00

How can I iterate over all documents matching each value of a specified key

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How can I iterate over all documents matching each value of a specified key in a MongoDB collection?

E.g. for a collection containing:

{ _id: ObjectId, keyA: 1 },
{ _id: ObjectId, keyA: 2 },
{ _id: ObjectId, keyA: 2 },

…with an index of { keyA: 1 }, how can I run an operation on all documents where keyA:1, then keyA:2, and so on?

Specifically, I want to run a count() of the documents for each keyA value. So for this collection, the equivalent of find({keyA:1}).count(), find({keyA:2}).count(), etc.

UPDATE: whether or not the keys are indexed is irrelevant in terms of how they’re iterated, so edited title and description to make Q/A easier to reference in the future.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-12T06:10:13+00:00Added an answer on June 12, 2026 at 6:10 am

    A simpler approach to get the grouped count of unique values for keyA would be to use the new Aggregation Framework in MongoDB 2.2:

    eg:

    db.coll.aggregate(
      { $group : {
         _id: "$keyA",
         count: { $sum : 1 }
      }}
    )
    

    … returns a result set where each _id is a unique value for keyA, with the count of how many times that value appears:

    {
        "result" : [
            {
                "_id" : 2,
                "count" : 2
            },
            {
                "_id" : 1,
                "count" : 1
            }
        ],
        "ok" : 1
    }
    
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