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Home/ Questions/Q 8812489
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T03:37:05+00:00 2026-06-14T03:37:05+00:00

how can I make the func. show all the bad values and not just

  • 0

how can I make the func. show all the bad values and not just one?

def get_bad_results(person_results):
        for i in person_results:
                if i[1]>i[3] or i[1]<i[2]:
                    return i[0]

test_results = [["White blood cells",8.5,2,7],
                ["Neutrophils",5.3,2.5,5],
                ["Red blood cells", 12.4, 9,15]]

a = get_bad_results(test_results)
print a

show White blood cells

instead of

White blood cells, Neutrophils
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-14T03:37:06+00:00Added an answer on June 14, 2026 at 3:37 am

    As you expect several results per call, it is the best to use a generator function:

    def get_bad_results(person_results):
        for i in person_results:
            if i[1]>i[3] or i[1]<i[2]:
                yield i[0]
    

    or a generator expression:

    def get_bad_results(person_results):
        return (i[0] for i in person_results if i[1]>i[3] or i[1]<i[2])
    

    so that

    test_results = [["White blood cells",8.5,2,7],
                    ["Neutrophils",5.3,2.5,5],
                    ["Red blood cells", 12.4, 9,15]]
    
    for i in get_bad_results(test_results):
        print i
    print list(get_bad_results(test_results))
    print ", ".join(get_bad_results(test_results))
    

    gives the output

    White blood cells
    Neutrophils
    ['White blood cells', 'Neutrophils']
    White blood cells, Neutrophils
    

    For the other function, do

    def count_healthy(all_results):
        counter = 0
        for i in all_results:
            if len(list(get_bad_results(i))) == 0:
                counter += 1
        return counter
    

    or just

    def count_healthy(all_results):
        return sum(1 for i in all_results if len(list(get_bad_results(i))) == 0)
    

    Edit:

    For many get_bad_results(), turning it into a list could be memory-intensive.

    So instead of len(list(get_bad_results(i))) == 0 you could use

    def has_results(it):
        """Returns True if the iterator it yields any items."""
        return next((True for _ in it), False)
    

    and then

    def count_healthy(all_results):
        return sum(1 for i in all_results if not has_results(get_bad_results(i)))
    
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