Question

How can i map a date from a java object to a database with Hibernate? I try different approaches, but i am not happy with them. Why? Let me explain my issue. I have the following class [1] including the main method i invoke and with the following mapping [2]. The issue about this approach you can see, when you look at the console output.

false

false

1

-1

1224754335648

1224754335000

Thu Oct 23 11:32:15 CEST 2008

Clock@67064

As you can see the the to dates are not exactly equal, although they should, so it is hard to compare them without goofing around with return value of getTime. I also tried java.sql.Date, Timestamp and date instead of timestamp in the mapping, but without success.

I wonder why the last three digits are zero and if this is a hibernate or a java issue or my own stupidity.

Thank you for reading.

[1]

public class Clock {      int id;     java.util.Date date;      public static void main(String[] args) {         HibernateUtil.init();         HibernateUtil.getSessionFactory().getCurrentSession().beginTransaction();          Clock clock = new Clock();         clock.date = new java.util.Date();          HibernateUtil.getSessionFactory().getCurrentSession().saveOrUpdate(clock);         HibernateUtil.getSessionFactory().getCurrentSession().getTransaction().commit();          HibernateUtil.getSessionFactory().getCurrentSession().beginTransaction();          Clock fromDBClock = (Clock)HibernateUtil.getSessionFactory()                         .getCurrentSession().get(Clock.class, 1);          System.out.println(clock.date.equals(fromDBClock.date));         System.out.println(fromDBClock.date.equals(clock.date));          System.out.println(clock.date.compareTo(fromDBClock.date));         System.out.println(fromDBClock.date.compareTo(clock.date));          System.out.println(clock.date.getTime());         System.out.println(fromDBClock.date.getTime());          System.out.println(clock.date.toString());         System.out.println(fromDBClock.toString());          HibernateUtil.getSessionFactory().getCurrentSession().getTransaction().commit();          HibernateUtil.end();     }      public int getId() {         return id;     }      public void setId(int id) {         this.id = id;     }      public java.util.Date getDate() {         return date;     }      public void setDate(java.util.Date date) {         this.date = date;     }   } 

[2]

<?xml version='1.0'?> <!DOCTYPE hibernate-mapping PUBLIC         '-//Hibernate/Hibernate Mapping DTD 3.0//EN'         'http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd'>  <hibernate-mapping>      <class name='Clock' table='CLOCK'>         <id name='id' column='CLOCK_ID'>             <generator class='native'/>         </id>         <property name='date' type='timestamp'/>       </class>  </hibernate-mapping> 

Answer 1

MySql DateTime precision is only to the second. Java Date precision is to the millisecond. That is why the last three digits are zeros after it has been put in the database.

Do this to your original Date:

date = date.setTime((date.getTime() / 1000) * 1000);

This will set it to the last exact second, and all your comparisons will then match.

(BTW, System.out.println(fromDBClock.toString()); should be System.out.println(fromDBClock.date.toString());