Question

How can I match only the exact inline code and match the two if’s twice, not as one match.

http://regexr.com?2uvul

I want to get result with:

Array(
[0] => asd
[1] => asd
)

not

Array(
[0] => asdasd
)

Answer 1

http://regexr.com?2uvuu — use the expression:

<!--\s+IF\s+([^\s]*)\s-->([^<]*)<!--\sENDIF\s-->

EDIT:

Considering that what you want to match inside the if statement “tag” might have white space, a slightly slower expression that should handle anything inside the “if statement” should be as follows (at RegExr):

/<!--\s+IF\s+(.*?)\s-->([^<]*)<!--\sENDIF\s-->/gixsm

If you then want to be able to capture other tags (or the character <) inside the result (if the statement is “true”, you will want to use the (again slightly slower) expression (at RegExr):

/<!--\s+IF\s+(.*?)\s-->(.*?)<!--\sENDIF\s-->/gixsm

END EDIT