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Home/ Questions/Q 7036321
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T01:24:37+00:00 2026-05-28T01:24:37+00:00

How can I output the below asterisks in rhombus shape in c++ using the

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How can I output the below asterisks in rhombus shape in c++ using the least number of loops and variables. Maximum no. of stars = n (input taken from the user)

  *
 * *
* * * = n
 * * 
  *

I tried doing it with just 2 loops but didn’t succeed plus the program is too complicated to understand so didn’t include it here.

So any algorithms you can think of?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-28T01:24:38+00:00Added an answer on May 28, 2026 at 1:24 am

    This is a common question for education I believe, and thus a Google search is very helpful.

    Here is a ready made solution in Visual C++ (as some people learn better from code examples, the choice is yours)…

    http://www.softwareandfinance.com/Visual_CPP/Loops_Diamond_Pattern.html

    EDIT: Trying to reduce the for loops and keeping the spacing between stars, this is my best effort…

    int i, j;
    int n = 0;
    std::cout << "Enter the maximum number of *:";
    std::cin >> n;
    
    std::cout << "\n\n";
    
    for (i = 1; i <= n; i++)
    {
          std::cout.width(n - i);
          std::cout.fill(' ');
          std::cout << "";
    
          for (j = 1; j <= i; j++)
                std::cout << "* ";
    
          std::cout.width(n - i);
          std::cout.fill(' ');
          std::cout << "";
    
          std::cout << "\n";
    }
    
    for (i = n - 1; i >= 1; i--)
    {
          std::cout.width(n - i);
          std::cout.fill(' ');
          std::cout << "";
    
          for (j = 1; j <= i; j++)
                std::cout << "* ";
    
          std::cout.width(n - i);
          std::cout.fill(' ');
          std::cout << "";
    
          std::cout << "\n";
    }
    
    std::cout << "\n";
    

    ONLY 2 LOOPS USED:

    int i, j;
    int n = 0, c = 0, inc = 1;
    std::cout << "Enter the maximum number of *:";
    std::cin >> n;
    
    std::cout <<"\n\n";
    
    for (i = 1; i <= (n * 2) - 1; i++)
    {
        c += inc;
        if(i == n)
            inc = -1;
    
        std::cout.width(n - c);
        std::cout.fill(' ');
        std::cout << "";
    
        for (j = 1; j <= c; j++)
            std::cout << "* ";
    
        std::cout.width(n - c);
        std::cout.fill(' ');
        std::cout << "";
    
        std::cout <<"\n";
    }
    
    std::cout <<"\n";
    
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