Question

How can I parse this date format? Should I change this colon to dot or maybe someone know better solution?

> x <- "2012.01.15 09:00:02:002"
> strptime(x, "%Y.%m.%d %H:%M:%S:%OS") 
[1] "2012-01-15 09:00:02"
> strptime(x, "%Y.%m.%d %H:%M:%OS")
[1] "2012-01-15 09:00:02"
> x <- "2012.01.15 09:00:02.002"
> strptime(x, "%Y.%m.%d %H:%M:%OS")
[1] "2012-01-15 09:00:02.001"

Answer 1

There’s a subtle distinction here that may be throwing you off.
As ?strptime notes:

for ‘strptime’ ‘%OS’ will input seconds including fractional seconds.

To emphasize that a bit, %OS represents the seconds including fractional seconds — not just the fractional part of the seconds: if the seconds value is 44.234, %OS or %OS3 represents 44.234, not .234

So the solution is indeed to substitute a . for that final :.

Here’s one way you might do that:

x <- "2012.01.15 09:00:02:002"
strptime(gsub(":", ".", x), "%Y.%m.%d %H.%M.%OS")