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Home/ Questions/Q 7183811
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T18:04:19+00:00 2026-05-28T18:04:19+00:00

How can I pass an argument in a function to create ID? For example

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How can I pass an argument in a function to create ID? For example in following I want ID_Name as to be taken as <div> ID. The following doesn’t work. Just to show my intention.

function create_drags(ID_Name) {
    $("BODY").append($('<div ID="ID_Name" class="ui-widget-content"><p>Draggable </p></div>'));
    $(ID_Name).draggable();
}

How can this be accomplished?

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  1. Editorial Team
    Editorial Team
    2026-05-28T18:04:20+00:00Added an answer on May 28, 2026 at 6:04 pm

    Updated:
    Here is a working fiddle for you to try. http://jsfiddle.net/etdKL/

    String concatenation.
    There are two problems
    The first when assigning the Id.
    Instead of ID="ID_Name" you type ID="'+ID_Name+'" Then JavaScript will evaluate ID_Name as a variable instead of a String literal.

    $("BODY").append($('<div ID="'+ID_Name+'" ...'
    

    The second is that you need to use a # in the selector to tell JQuery to use the ID selector resulting in.

    $(ID_Name) --> $('#' +ID_Name)
    
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