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Home/ Questions/Q 7991613
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Editorial Team
  • 0
Editorial Team
Asked: June 4, 20262026-06-04T13:20:28+00:00 2026-06-04T13:20:28+00:00

How can I read the latest number from the following code <table width=100 border=1

  • 0

How can I read the latest number from the following code

<table  width="100" border="1" >
   <tr align="center" bgcolor="#999999" >
     <td  >NO</td>
     <td  >Name</td>
     <td  >PBSID</td>
   </tr>

$query ="select * from stock ";
$hasil = mysql_query($query); 
$no=0;

while ($row = mysql_fetch_array($hasil))
{ 
    $no++;
    if($x != $row[pbsid] )
    { 
        $no=1;
        echo "<tr bgcolor=#CCCCCC>
                  <td colspan=4 ><b> GROUP $row[pbsid]</b></td>
              </tr>";
    }

    $mo=count($no);
    echo "<tr><td>$no </td><td> $row[bnama]</td><td>$row[pbsid] </td></tr>";
    $x = $row["pbsid"];
}

The result:


===========
NO | NAME | GROUP
---------------------------------------
===========
GROUP 1
---------------------------------------
===========
1 | A | 1    
2 | B | 1    
3 | C | 1    
4 | D | 1
---------------------------------------
===========
GROUP 2
---------------------------------------
===========
1 | A | 2    
2 | B | 2    
3 | C | 2

I want to show the latest GROUP number, Group 1=4 and Group 2=3, can anyone help me with this?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-04T13:20:30+00:00Added an answer on June 4, 2026 at 1:20 pm

    Try this query:

    SELECT s.*, c.count
    FROM stock AS s
    LEFT JOIN ( SELECT pbsid, COUNT(1) AS `count` FROM stock GROUP BY pbsid ) AS c
        ON s.pbsid = c.pbsid
    

    Now you will have the count for each group, which is what it seems you really want.

    If you’d prefer to do all the work in PHP for some reason, you could do it like this:

    <table  width="100" border="1" >
       <tr align="center" bgcolor="#999999" >
         <td  >NO</td>
         <td  >Name</td>
         <td  >PBSID</td>
       </tr>
    
    $query ="select * from stock ";
    $hasil = mysql_query($query); 
    $no=0;
    
    $counts = array();  // make an array of counts for each group, keyed by pbsid
    $rows = array();  // put all the data from SQL into an array
    while ($row = mysql_fetch_array($hasil))
    {
        $rows[] = $row;
        if (!isset($counts[$row[pbsid]]))
        {
            $counts[$row[pbsid]] = 0; // initialize it to 0
        }
        $counts[$row[pbsid]]++; // increment for each occurrence of a pbsid 
    }
    
    foreach ($rows as $row)
    { 
        $no++;
        if($x != $row[pbsid] )
        { 
            $no=1;
            echo "<tr bgcolor=#CCCCCC>
                      <td colspan=4 ><b> GROUP $row[pbsid]</b> Count = " . $counts[$row[pbsid]] . " </td>
                  </tr>";
        }
    
        $mo=count($no);
        echo "<tr><td>$no </td><td> $row[bnama]</td><td>$row[pbsid] </td></tr>";
        $x = $row["pbsid"];
    }
    

    Although, I think it’s much simpler to just have this information calculated in your query.

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